Template:Diagnostic testing example
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| Fecal occult blood screen test outcome | |||||
| Total population (pop.) = 2030 | Test outcome positive | Test outcome negative | Accuracy (ACC) = (TP + TN) / pop. = (20 + 1820) / 2030 ≈ 90.64% | F1 score = 2 × precision × recall/precision + recall ≈ 0.174 | |
| Patients with bowel cancer (as confirmed on endoscopy) | Actual condition positive (AP) = 30 (2030 × 1.48%) | True positive (TP) = 20 (2030 × 1.48% × 67%) | False negative (FN) = 10 (2030 × 1.48% × (100% − 67%)) | True positive rate (TPR), recall,   sensitivity = TP / AP = 20 / 30 ≈ 66.7% | False negative rate (FNR), miss rate = FN / AP = 10 / 30 ≈ 33.3% | 
| Actual condition negative (AN) = 2000 (2030 × (100% − 1.48%)) | False positive (FP) = 180 (2030 × (100% − 1.48%) × (100% − 91%)) | True negative (TN) = 1820 (2030 × (100% − 1.48%) × 91%) | False positive rate (FPR), fall-out, probability of false alarm = FP / AN = 180 / 2000 = 9.0% | Specificity, selectivity, true negative rate (TNR) = TN / AN = 1820 / 2000 = 91% | |
| Prevalence = AP / pop. = 30 / 2030 ≈ 1.48% | Positive predictive value (PPV), precision = TP / (TP + FP) = 20 / (20 + 180) = 10% | False omission rate (FOR) = FN / (FN + TN) = 10 / (10 + 1820) ≈ 0.55% | Positive likelihood ratio (LR+) = TPR/FPR = (20 / 30) / (180 / 2000) ≈ 7.41 | Negative likelihood ratio (LR−) = FNR/TNR = (10 / 30) / (1820 / 2000) ≈ 0.366 | |
| False discovery rate (FDR) = FP / (TP + FP) = 180 / (20 + 180) = 90.0% | Negative predictive value (NPV) = TN / (FN + TN) = 1820 / (10 + 1820) ≈ 99.45% | Diagnostic odds ratio (DOR) = LR+/LR− ≈ 20.2 | |||
